First find the distribution load:
The area of the crate = 1.75ft x 1.25ft = 2.18 sq.ft
Divide the mass by the area to find the distribution load.
174 kg / 2.18 sq.ft = 79.81 kg/sq.ft
Now find the running/linear load and assume you load the pallet on to the aircraft on its longest...
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Where the weight line crosses the edge of the CG envelope parallel the 'fan' lines, either up or down, to read the MAC. If you go up you get a more accurate reading because of the larger scale.
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block fuel is the fuel in the tanks prior to engine start.
Trip fuel is the fuel required to get from A to B
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Hi Stef
The reason the flight fuel moment is given in the example is to simplify the calculation because the trip fuel comes from the centre tank and the wing tanks. Clearly both have different arms. These can be found in CAP696 section 4 page 3 fig 4.5.
At takeoff the centre tank will...
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Fig 2.1 You would use the shortest after applying the regulation factors. See example in section 2 page 4. In this case it would be the ASDA defactored by 1.3. 2500/1.3 = 1923ft
Fig 2.4 you would ignore the upslope. See CAP 698 section 2 page 9 para 5.1.d. The LDA would need to defactored by...
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Have a look at 320123. This will show you how to tackle these questions.
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The current CG is at 22.62m. The middle of the limits is 20m. Required change in CG is 2.62m.
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Hi Liam
was there an answer that matched the limits for the MLM?
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First of all the value given is an N1 setting not EPR.
The engine is pressure limited in the flat rating cutoff area.
If you look at 30C and zero PA we set 96.1%, the engine has become flat rated due to the mass flow/pressure limitation. Now look at 0C and PA zero where we set 91.2%.This...
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On your first question: T/O on short grass increases the T/O distance by 1.2. Landing on short grass increases the landing distance by 1.15. See CAP698.
On your second question:
I think you are referring to QID 320010
An aeroplane executes a steady glide at the speed...
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Use this formula:
Change in mass/New total mass = change in CG/Distance from mass to old CG
Substitute known values:
16/113 = change in CG/+3
Transpose to find change in CG
Change in CG = +3 x 16/113
=+0.42ft
The + sign in the question tells us that the...
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