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  • Q330007

    Hello, this is probably a simple algebra question but I am not getting the reasoning behind it in the explanation. Could someone elaborate on the formula used?

    For a planned flight the calculated fuel is as follows:
    Trip length is 3:36.
    Reserve fuel is 30% of trip fuel.
    Taxi fuel is 20 kg
    Block fuel is 250 kg
    What fuel remains after 2 h 24 min?

    Take-off fuel = TRIP(100% TRIP) + RESERVE (30% TRIP) = 130% x TRIP

    Take-off fuel = 1.3 x TRIP

    Take-off fuel = (250

  • #2
    Block fuel is fuel on Blocks (at the ramp) and so you must subtract taxi fuel to find Take off fuel. 250 -20 = 230 kg

    230 kg = 130 % of trip

    230 kg
    BGS TKI

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    • #3
      System problem; to continue:

      Block fuel is fuel on Blocks (at the ramp) and so you must subtract taxi fuel to find Take off fuel (250 kg - 20 = 230 kg)

      230 Kg is 130 % of trip

      230 / 1.3 = Trip 177 kg 230 - 177 = Reserves 53 Kg

      Trip time 3.36 = 3.6 hours

      After 2.24 = 2.4 hours. Then 1.2 hours remain.

      Fuel flow is 177 Kg / 3.6 hours = 49.2 Kg / hour

      Trip fuel remaining = 1.2 hours x 49.2 fuel flow = 59 Kg

      Total Fuel remaining = 59 Kg Trip + 53 Kg reserves = 112 Kg
      BGS TKI

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      • #4
        Thank you MAC. I was getting confused re the 130% bit. Cleared up now , cheers

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        • #5
          Your welcome!
          BGS TKI

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